-
Question
Q:- The speed of a car increases with constant acceleration for 46 seconds. Its Initial Speed is 18 meters/second and Final Speed is 570 meters/second.
Find [1] How much was the acceleration.
Find [2] How much distance did the car travel
-
Step : 1
Final Speed = Initial Speed + Acceleration x Time of Acceleration
570 = 18 + A x 46
( 570 - 18 ) / 46 = A = 12 meters/second2
-
Step : 2
Average Speed (when acceleration is constant)= [(Initial Speed + Final Speed) /2 ]
Sav = [ (18 + 570)/2 ] = 294 meters/second
-
Step : 3
Distance Travelled= Average Speed x Time of Acceleration
D = 294 x 46 = 13524 meters
Calculation Speed Booster
✈ Click on the 《more so》 button in the timer panel .
✈Another question will appear with different numerical values .
✈Now try to solve it faster.
✈Check your speed by the timer.
✈Share your speed on
✈Share your speed on
✈
JOIN our TELEGRAM group : @AptitudeMathSpeedBoosterEatMaths
.
Want some question of your choice
If you want to practice some questions which are not available here then send us the details of the question in our whatsapp 7291934297.
Want to practice on hundreds of varity of such questions
Call 7463918936, and book your limited premium membership. Monthly rupees 150/- only. Online tutorial classes also available seprately for making your basics and theory strong.