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Question
Q:- The speed of a car increases with constant acceleration of 9 meters/second2. Its Final Speed is 19 meters/second, and Distance travelled in the time of this acceleration is 11 meters
Find [1] How much is its Initial speed.
Find [2] How much time of travel
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Step : 1
[ Final Speed{2} - Initial Speed{2}] = [ 2 x Distance Travelled] x [ Acceleration ]
=> [ Final Speed{2}- Initial Speed{2}] = [ 2 x 11] x [ 9 ]
=> [ Final Speed{2} ] - [ 2 x 11] x [ 9 ] = Initial Speed{2}
=>square root of ( [pow(19,2)] - [ 2 x 11] x [ 9 ]) = Initial Speed = 12.767145334804 meters/second
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Step : 2
Average Speed (when acceleration is constant)= [(Initial Speed + Final Speed) /2 ]
=>Sav = [ (12.767145334804 + 19)/2 ] = 15.883572667402 meters/second
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Step : 3
Distance Travelled= Average Speed x Time of Acceleration
=>Distance Travelled / Average Speed = Time of Acceleration
=>11 / 15.883572667402 = 0.69253940724403 seconds
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