-
Question
Q:- The speed of a car increases with constant acceleration of 12 meters/second2 for 47 seconds. And Distance travelled in the time of this acceleration is 14100 meters
Find [1] How much is its Initial speed.
Find [2] How much is its Final speed.
-
Step : 1
Final Speed = Initial Speed + Acceleration x Time of Acceleration
Final Speed - Initial Speed =Acceleration x Time of Acceleration = 12 x 47 = 564 meters/second
-
Step : 2
Distance Travelled= [(Initial Speed + Final Speed) /2 ] x Time of Acceleration
2 x Distance Travelled x Time of Acceleration= [(Initial Speed + Final Speed) ] = 2 x 14100 / 47 = 600 meters/second
-
Step : 3
Final Speed - Initial Speed = 564 meters/second
Final Speed + Initial Speed = 600 meters/second
-
Step : 4
( Final Speed + Initial Speed ) + ( Final Speed - Initial Speed ) = 600 + 564 meters/second
2 x ( Final Speed ) = 600 + 564 meters/second
( Final Speed ) = ( 600 + 564 )/2 meters/second = 582 meters/second
-
Step : 5
( Final Speed + Initial Speed ) - ( Final Speed - Initial Speed ) = 600 - 564 meters/second
2 x ( Initial Speed ) = 600 - 564 meters/second
( Initial Speed ) = ( 600 - 564 )/2 meters/second = 18 meters/second
Calculation Speed Booster
✈ Click on the 《more so》 button in the timer panel .
✈Another question will appear with different numerical values .
✈Now try to solve it faster.
✈Check your speed by the timer.
✈Share your speed on
✈Share your speed on
✈
JOIN our TELEGRAM group : @AptitudeMathSpeedBoosterEatMaths
.
Want some question of your choice
If you want to practice some questions which are not available here then send us the details of the question in our whatsapp 7291934297.
Want to practice on hundreds of varity of such questions
Call 7463918936, and book your limited premium membership. Monthly rupees 150/- only. Online tutorial classes also available seprately for making your basics and theory strong.