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Question
Q:- The speed of a car increases with constant acceleration of 18 meters/second2 for 21 seconds. And Distance travelled in the time of this acceleration is 4137 meters
Find [1] How much is its Initial speed.
Find [2] How much is its Final speed.
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Step : 1
Final Speed = Initial Speed + Acceleration x Time of Acceleration
Final Speed - Initial Speed =Acceleration x Time of Acceleration = 18 x 21 = 378 meters/second
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Step : 2
Distance Travelled= [(Initial Speed + Final Speed) /2 ] x Time of Acceleration
2 x Distance Travelled x Time of Acceleration= [(Initial Speed + Final Speed) ] = 2 x 4137 / 21 = 394 meters/second
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Step : 3
Final Speed - Initial Speed = 378 meters/second
Final Speed + Initial Speed = 394 meters/second
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Step : 4
( Final Speed + Initial Speed ) + ( Final Speed - Initial Speed ) = 394 + 378 meters/second
2 x ( Final Speed ) = 394 + 378 meters/second
( Final Speed ) = ( 394 + 378 )/2 meters/second = 386 meters/second
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Step : 5
( Final Speed + Initial Speed ) - ( Final Speed - Initial Speed ) = 394 - 378 meters/second
2 x ( Initial Speed ) = 394 - 378 meters/second
( Initial Speed ) = ( 394 - 378 )/2 meters/second = 8 meters/second
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