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Question
Q. First term is of arithmatic progression sequence is 48 and the difference between consecutive numbers is 10 , Find the numbers from 43 to 47 terms.
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Step : 1
Term at 43 position is 48 + (43 - 1)x 10
= 468 (=t1)
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Step : 2
Term at 44 position is 48 + (44 - 1)x 10
= 478 (=t2)
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Step : 3
Term at 45 position is 48 + (45 - 1)x 10
= 488 (=t3)
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Step : 4
Term at 46 position is 48 + (46 - 1)x 10
= 498 (=t4)
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Step : 5
Term at 47 position is 48 + (47 - 1)x 10
= 508 (=t5)
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Step : 6
so the sequance of numbers from position 43 to 47 is 468, 478, 488, 498, 508
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