-
Question
Q. First term is of arithmatic progression sequence is 49 and the difference between consecutive numbers is 9 , Find the numbers from 27 to 31 terms.
-
Step : 1
Term at 27 position is 49 + (27 - 1)x 9
= 283 (=t1)
-
Step : 2
Term at 28 position is 49 + (28 - 1)x 9
= 292 (=t2)
-
Step : 3
Term at 29 position is 49 + (29 - 1)x 9
= 301 (=t3)
-
Step : 4
Term at 30 position is 49 + (30 - 1)x 9
= 310 (=t4)
-
Step : 5
Term at 31 position is 49 + (31 - 1)x 9
= 319 (=t5)
-
Step : 6
so the sequance of numbers from position 27 to 31 is 283, 292, 301, 310, 319
Calculation Speed Booster
✈ Click on the 《more so》 button in the timer panel .
✈Another question will appear with different numerical values .
✈Now try to solve it faster.
✈Check your speed by the timer.
✈Share your speed on
✈Share your speed on
✈
JOIN our TELEGRAM group : @AptitudeMathSpeedBoosterEatMaths
.
Want some question of your choice
If you want to practice some questions which are not available here then send us the details of the question in our whatsapp 7291934297.
Want to practice on hundreds of varity of such questions
Call 7463918936, and book your limited premium membership. Monthly rupees 150/- only. Online tutorial classes also available seprately for making your basics and theory strong.