• Q. First term is of arithmatic progression sequence is 30 and the difference between consecutive numbers is 11 , Find the sum numbers 25th, 26th, 27th, 28th and 29th terms.
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  • Sum of 25 position is (25/2)[2*30 + (25 - 1)x 11 ]

    = (12.5)[60 + (24)x 11 ]

    = (12.5)[60 + 264 ]

    = (12.5)[324]

    ie. S25 = (4050)

  • Sum of 26 position is (26/2)[2*30 + (26 - 1)x 11 ]

    = (13)[60 + (25)x 11 ]

    = (13)[60 + 275 ]

    = (13)[335]

    ie. S26 = (4355)

  • Sum of 27 position is (27/2)[2*30 + (27 - 1)x 11 ]

    = (13.5)[60 + (26)x 11 ]

    = (13.5)[60 + 286 ]

    = (13.5)[346]

    ie. S27 = (4671)

  • Sum of 28 position is (28/2)[2*30 + (28 - 1)x 11 ]

    = (14)[60 + (27)x 11 ]

    = (14)[60 + 297 ]

    = (14)[357]

    ie. S28 = (4998)

  • Sum of 29 position is (29/2)[2*30 + (29 - 1)x 11 ]

    = (14.5)[60 + (28)x 11 ]

    = (14.5)[60 + 308 ]

    = (14.5)[368]

    ie. S29 = (5336)

  • so the sequance of the sum numbers from position are.
    S25 = 4050
    S26 = 4355
    S27 = 4671
    S28 = 4998
    S29 = 5336

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