• Q. In a G.P., the 6th term is 1215 and the 10th term is 98415 . Find the first term(a), common ratio(r) and 15th term.
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  • solve:-
    Here,
    a6 = ar5 = 1215 .............. 1
    and,
    a10 = ar9 = 98415 .............. 2

    Dividing equation (2) by (1), we get.

    [ar9]/[ar5] = [98415]/[1215]
    => r4 = 81
    => r4 = 34
    => r = 3


  • Equation (1) we get
    ar5 = 1215
    => a35 = 1215
    => a * 243 = 1215
    => a = 1215 / 243
    => a = 5
    ie. a = 5 and r = 3


  • Now,
    Here, first term = 5,
    common ratio = 3
    then,
    15th term is = 5*3 (15 - 1)
    = 5*3 14
    = 5*4782969
    => 15th term is = 23914845

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