solve:-
Term at 6 position is 18 *2^(6-1)
= 18 *2⁽⁵⁾
= 18 * 32
= 576

Now,
The sum of 6 to 10 position is 576*[1 - 2⁽⁵⁾] /[1-2]
= (576)[ 1 - 2⁽⁵⁾]/[1-2]

= (576)(-31)/(-1)

= (576)(31)

ie. S₆ to S₁₀ = 17856

Second method:-
Term at 6 position is 18 *2^(6-1)
= 18 *2⁽⁵⁾

= 18 * 32
= 576 (=t1)

Term at 7 position is 18 *2^(7-1)
= 18 *2⁽⁶⁾

= 18 * 64
= 1152 (=t2)

Term at 8 position is 18 *2^(8-1)
= 18 *2⁽⁷⁾

= 18 * 128
= 2304 (=t3)

Term at 9 position is 18 *2^(9-1)
= 18 *2⁽⁸⁾

= 18 * 256
= 4608 (=t4)

Term at 10 position is 18 *2^(10-1)
= 18 *2⁽⁹⁾

= 18 * 512
= 9216 (=t5)

so the sequance of numbers from position 6 to 10 are 576, 1152, 2304, 4608, 9216
= 576 + 1152 + 2304 + 4608 + 9216;

= 17856