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Question

Q. First term is of arithmatic progression sequence is 26 and the difference between consecutive numbers is 7 , Find the numbers from 10 to 14 terms.

Step : 1

Term at 10 position is 26 + (10 - 1)x 7
= 89 (=t1)

Step : 2

Term at 11 position is 26 + (11 - 1)x 7
= 96 (=t2)

Step : 3

Term at 12 position is 26 + (12 - 1)x 7
= 103 (=t3)

Step : 4

Term at 13 position is 26 + (13 - 1)x 7
= 110 (=t4)

Step : 5

Term at 14 position is 26 + (14 - 1)x 7
= 117 (=t5)

Step : 6

so the sequance of numbers from position 10 to 14 is 89, 96, 103, 110, 117

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